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09012007  #61 
Join Date: Oct 2006
Posts: 822

No, it's
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09012007  #62 
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Fine, whatever. Next question.

09012007  #63 
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09022007  #64 
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09022007  #65 
Join Date: Oct 2006
Posts: 822

VERY nonwhole. All you do is put them in slope intercept form, put two of them at a time to be equal, find the coordinates that way, and use shoelace or whatever method you want to.
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09022007  #66 
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Do we really have to solve the problem? Come on, I mean...

09022007  #67 
Join Date: Oct 2006
Posts: 822

Do we have to do all that "figuring out" stuff
/whine
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09082007  #68 
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\sigh This is a long one. Time to play with graphing programs.
So you have three sets of linear equations for each vertex of the triangle. Each solution for each on is So take the midpoint of and which is . Now take the distance between the midpoint and two endpoints, and multiply the two distances and divide by two to get the answer. I have to go soon so someone can finish it up. 
10292007  #69 
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Eh, I decided to revive this thread.
Find the volume of a tetrahedron with a surface area of 361 square meters. 
10292007  #70 
Join Date: Oct 2006
Posts: 822

Regular or not?
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